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(2x+5)+(x^2+25)=0
We get rid of parentheses
x^2+2x+5+25=0
We add all the numbers together, and all the variables
x^2+2x+30=0
a = 1; b = 2; c = +30;
Δ = b2-4ac
Δ = 22-4·1·30
Δ = -116
Delta is less than zero, so there is no solution for the equation
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